3x(x+1)(2x-7)(3x+4)^2(x-13)(x+7)=0

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Solution for 3x(x+1)(2x-7)(3x+4)^2(x-13)(x+7)=0 equation: 



3x(x+1)(2x-7)(3x+4)^2(x-13)(x+7)=0

We multiply parentheses ..

3x(+2x^2-7x+2x-7)(3x+4)^2(x-13)(x+7)=0

We multiply parentheses ..

3x(+2x^2-7x+2x-7)(3x+4)^2(+x^2+7x-13x-91)=0

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